(x+1)(x^2-4x+3)=

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Solution for (x+1)(x^2-4x+3)= equation:


Simplifying
(x + 1)(x2 + -4x + 3) = 0

Reorder the terms:
(1 + x)(x2 + -4x + 3) = 0

Reorder the terms:
(1 + x)(3 + -4x + x2) = 0

Multiply (1 + x) * (3 + -4x + x2)
(1(3 + -4x + x2) + x(3 + -4x + x2)) = 0
((3 * 1 + -4x * 1 + x2 * 1) + x(3 + -4x + x2)) = 0
((3 + -4x + 1x2) + x(3 + -4x + x2)) = 0
(3 + -4x + 1x2 + (3 * x + -4x * x + x2 * x)) = 0
(3 + -4x + 1x2 + (3x + -4x2 + x3)) = 0

Reorder the terms:
(3 + -4x + 3x + 1x2 + -4x2 + x3) = 0

Combine like terms: -4x + 3x = -1x
(3 + -1x + 1x2 + -4x2 + x3) = 0

Combine like terms: 1x2 + -4x2 = -3x2
(3 + -1x + -3x2 + x3) = 0

Solving
3 + -1x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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